van input array naar insert database

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Murti Aydogdu

Murti Aydogdu

02/03/2015 10:54:49
Quote Anchor link
Hallo allemaal ik werk aan een project waar bij in factuur kunt maken maar ik kan het alleen niet inserten in de database dit is de uitkomst in

Code (php)
PHP script in nieuw venster Selecteer het PHP script
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The Key is 0 with a value of Hardware
The Key is 1 with a value of Software
The Key is 0 with a value of reperatie
The Key is 1 with a value of website maken
The Key is 0 with a value of 1
The Key is 1 with a value of 1
The Key is 0 with a value of 30
The Key is 1 with a value of 500
string(126) "INSERT into hulptabel (ID, FactuurNR, Product,ProdOms,Aantal, Prijs) VALUES ('11','113' ,'Software','website maken','1','500')"


het zet het in een array dat werkt prima alleen met het inserten lukt het niet helemaal het insert alleen de laatst ingevulde tekstvak
Gewijzigd op 02/03/2015 11:00:21 door Murti Aydogdu
 
PHP hulp

PHP hulp

25/04/2024 21:36:27
 
- Ariën -
Beheerder

- Ariën -

02/03/2015 10:59:40
Quote Anchor link
Kom eens met relevante code aan, dan kunnen we wat meer vertellen.
 
Murti Aydogdu

Murti Aydogdu

02/03/2015 11:03:46
Quote Anchor link
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
<button id="remove_field">x</button>
Code (php)
PHP script in nieuw venster Selecteer het PHP script
1
<?php $query = mysql_query("SELECT * FROM producten"); ?>

<select name="Producten[]" id="Producten">
<div>
Code (php)
PHP script in nieuw venster Selecteer het PHP script
1
2
3
<?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>

</div><input type="text" name="ProdOms[]">
<input type="text" size="3" name="Aantal[]">
<input type="text" size="3" name="Prijs[]">
<a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
</select>
</div>

van dit heb ik er 15 in totaal en dit is de php code

Code (php)
PHP script in nieuw venster Selecteer het PHP script
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foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

[size=xsmall][i]Toevoeging op 02/03/2015 11:06:49:[/i][/size]

[quote="Murti Aydogdu op 02/03/2015 11:03:46"]
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }
[/quote]

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database


[size=xsmall][i]Toevoeging op 02/03/2015 11:07:23:[/i][/size]

[quote="Murti Aydogdu op 02/03/2015 11:03:46"]
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

[size=xsmall][i]Toevoeging op 02/03/2015 11:06:49:[/i][/size]

[quote="Murti Aydogdu op 02/03/2015 11:03:46"]
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }
[/quote]

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database

[/quote]



[size=xsmall][i]Toevoeging op 02/03/2015 11:08:13:[/i][/size]


Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database





[size=xsmall][i]Toevoeging op 02/03/2015 11:08:59:[/i][/size]

Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database







[size=xsmall][i]Toevoeging op 02/03/2015 13:58:13:[/i][/size]

iemand die het weet het moet

[size=xsmall][i]Toevoeging op 02/03/2015 13:58:41:[/i][/size]

[quote="Murti Aydogdu op 02/03/2015 11:03:46"]
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

[size=xsmall][i]Toevoeging op 02/03/2015 11:06:49:[/i][/size]

[quote="Murti Aydogdu op 02/03/2015 11:03:46"]
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }
[/quote]

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database


[size=xsmall][i]Toevoeging op 02/03/2015 11:07:23:[/i][/size]

[quote="Murti Aydogdu op 02/03/2015 11:03:46"]
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

[size=xsmall][i]Toevoeging op 02/03/2015 11:06:49:[/i][/size]

[quote="Murti Aydogdu op 02/03/2015 11:03:46"]
Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }
[/quote]

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database

[/quote]



[size=xsmall][i]Toevoeging op 02/03/2015 11:08:13:[/i][/size]


Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database





[size=xsmall][i]Toevoeging op 02/03/2015 11:08:59:[/i][/size]

Oke Aar dit is mijn html code

<div class="input_fields_wrap">
                        <button  id="remove_field">x</button>             
                        <?php $query = mysql_query("SELECT * FROM producten"); ?>
                        <select name="Producten[]" id="Producten">
                        <div><?php while($row = mysql_fetch_array($query)){
                                        echo "<option>" . $row['Producten'] . "</option>";
                                    }?>
                        </div><input type="text" name="ProdOms[]">
                              <input type="text" size="3" name="Aantal[]">
                              <input type="text" size="3" name="Prijs[]">
                              <a href="javascript:void(0)" onclick="toggle_visibility('popup-box1');"><img src="../img/icons/info.png" height="16" width="16"></a>
                        </select>
                    </div>

van dit heb ik er 15 in totaal en dit is de php code

foreach($_POST['Producten'] as $key => $Producten) {
                    echo 'The Key is '.$key. ' with a value of '.$Producten.'<br/>';
                }
                foreach($_POST['ProdOms'] as $key => $ProdOms){
                    echo 'The Key is '.$key. ' with a value of '.$ProdOms.'<br/>';
                }
                foreach($_POST['Aantal'] as $key => $Aantal){
                    echo 'The Key is '.$key. ' with a value of '.$Aantal.'<br/>';
                }
                foreach($_POST['Prijs'] as $key => $Prijs){
                    echo 'The Key is '.$key. ' with a value of '.$Prijs.'<br/>';
                }

ik moet de Produten, ProdOms, Aantal, Prijs inserten in de database







[size=xsmall][i]Toevoeging op 02/03/2015 13:58:13:[/i][/size]

iemand die het weet hoe moet
[/quote]
Gewijzigd op 02/03/2015 11:04:14 door Murti Aydogdu
 



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