picture.php

Ik ben nog een leek. Bezig met experimenteren.
Wie kan mij zeggen/schrijven hoe het file "picture.php" eruit moet zien/bevatten?

bedankt.

Henny

<script language="JavaScript">
<!--
function gb_p(Image,imgWidth,imgHeight) {
var border = 24;
var img = Image;
var features;
var w;
var h;
winWidth = (imgWidth<100) ? 100 : imgWidth+border;
winHeight = (imgHeight<100) ? 100 : imgHeight+border;
if (imgWidth+border > screen.width) {
winWidth = screen.width-10;
w = (screen.width - winWidth)/2;
features = "scrollbars=yes";
} else {
w = (screen.width - (imgWidth+border))/2;
}
if (imgHeight+border > screen.height) {
winHeight = screen.height-60;
h = 0;
features = "scrollbars=yes";
} else {
h = (screen.height - (imgHeight+border))/2 - 20;
}
winName = (img.indexOf("t_") == -1) ? img.substr(4,(img.length-8)) : img.substr(6,(img.length-10));
features = features+',toolbar=no,width='+winWidth+',height='+winHeight+',top='+h+',left='+w;
theURL = '/picture.php?img='+Image;
popup = window.open(theURL,winName,features);
popup.focus();
}


// -->
</script>

<a href="javascript:gb_p('img-foto01102.jpg',160,240)">zonnepanelen</a>