Ik wil een jpeg wijzigen naar 400x.....
Ik krijg steeds een zwarte afbeelding !!!!
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
<link href="gebruikersbeheer.css" rel="stylesheet" type="text/css" />
</head>
<body>
<div id="container">
<?php
$tempfile="fffff.jpg";
$dir= "fotos/";
$file="ffff2.jpg";
list($width, $height, $type, $attr) = getimagesize("$dir$tempfile");
echo "<img src=\"fotos/fffff.jpg\" $attr alt=\"getimagesize() example\" /><br>";
echo $width."<br>";
echo $height."<br>";
$verhouding= $width/$height;
echo $type."<br>";
echo $attr."<br>";
$mimage = @imagecreatefromjpeg($tempfile);
$im = @imagecreatetruecolor((400),(300));
@imagecopyresampled($im,$mimage,0,0,0,0,400,(400*$verhouding),$width,$height);
@imagejpeg($im, $dir.$file, 100);
list($width, $height, $type, $attr) = getimagesize("$dir$file");
echo "<img src=\"fotos/ffff2.jpg\" $attr alt=\"getimagesize() example\" /><br>";
echo $width."<br>";
echo $height."<br>";
echo $type."<br>";
echo $attr."<br>";
?>
</div>
<div id="code">
<?php
$filename = basename($_SERVER['PHP_SELF']);
highlight_file($filename);
?>
</div>
</body>
</html>
ik zie het niet :-(
-knopje willen gebruiken?