<?php
include('db/db.php');
if(isset($_SESSION['user']))
{
$user = $_SESSION['user'];
$result = mysql_query("SELECT * FROM user WHERE login='".$user."'");
$count = mysql_fetch_assoc($result);
$cc = $count['count'];
$ccc = $count['level'];
?>
met dit script geeft hij deze error
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in C:\www\hacker\status_check.php on line 7
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