Het formulier ziet er zo uit:
<form action="content/cms/login.php" id="loginform" method="post" onsubmit="submitForm('loginform');return false">
...
</form>De functie submitForm() ziet er zo uit:
function submitForm(formid,field) {
$form = $("#" + formid);
$.ajax({
type: "POST",
url: $form.attr("action"),
data: $form.serialize(),
error: function(r,s,e) {
alert("error in submitting form \"" + formid + "\":\n\n" + r + " - " + s + " - " + e);
},
succes: function(data,s) {
alert("data received after submitting form \"" + formid + "\":\n\n" + data);
}
});
}De code van content/cms/login.php is:
<?php
echo 'form submitted';
?>