ik krijg nu alleen de gegevens van 1 id terug?
wie kan mij hierin helpen.
<?
// Connecten met database
include("config.inc.php");
if(empty($_POST)){
$sql = "SELECT weeknr FROM werkoverzicht";
}
else {
$sql = "SELECT * FROM werkoverzicht WHERE weeknr='".mysql_real_escape_string($_POST["weeknr"])."'";
}
$result = mysql_query($sql);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?
if (empty($_POST)){
?>
<h2>kies weeknr</h2>
<form name="form1" action="<? echo($_SERVER["PHP_SELF"]); ?>" method="post">
<p>weeknr:
<select name="weeknr">
<?
while ($row=mysql_fetch_array($result,MYSQL_ASSOC)){
echo("<option value='" .$row['weeknr']. "'>" .$row['weeknr']. "</option>");
}
?>
</select>
<input type="submit" value="Tonen" />
</p>
</form>
<p>
<?
}else{
echo("<h2>Doorgegeven weeknr: " .$_POST["weeknr"]. "</h2>\n");
if ($row = mysql_fetch_array($result,MYSQL_ASSOC)){
echo("ID = " . $row['id'] . "<br>\n");
echo("weeknr = " . $row['weeknr'] . "<br>\n");
echo("dag = " . $row['dag'] . "<br>\n");
echo("omschrijving = " . $row['omschrijving'] . "<br>\n");
echo("<a href=\"" . $_SERVER["PHP_SELF"] . "\">Ander weeknr selecteren</a>");
}
}
?>
</p>
<p>
</p>
</body>
</html>