ik kom niet uit deze query:
mysql_query('SELECT * FROM users WHERE username=' . $_GET['user']);
als ik:
WHERE username=' . $_GET['user']
weghaal doet het wel maar als ik het er wel neerzet krijg ik error.
mvg: Lex van der Poel
mysql_query('SELECT * FROM users WHERE username=' . $_GET['user']);
WHERE username=' . $_GET['user']
mysql_query("SELECT * FROM users WHERE username=' . $_GET['user'] . '");
mysql_query("SELECT * FROM users WHERE username='" . $_GET['user'] . "'");
$result = mysql_query("SELECT * FROM users WHERE username = '" . mysql_real_escape_string($_GET['user']) . "'");
if(strlen(mysql_fetch_array($result)) == 0){
echo "User bestaat niet!";
} else {
while ($row = mysql_fetch_array($result)) {
echo "<ul><table><tr><td width=\"150px\"><li>Username: </td><td>" . $row["username"] . "</li></td></tr><tr><td><li>Firstname: </td><td>" . $row["firstname"] . "</li></td></tr><tr><td><li>Lastname: </td><td>" . $row["lastname"] . "</li></td></tr><tr><td><li>Registered since: </td><td>" . $row["regsince"] . "</li></td></tr><tr><td><li>Lastlogin: </td><td>" . $row["lastlogin"] . "</li></td></tr><tr><td><li>Online time: </td><td>" . $row["onlinetime"] . "</li></td></tr></table></ul>";
}
}
Lex van der poel op 12/03/2012 18:57:09
ik heb nu dit:
if(strlen(mysql_fetch_array($result)) == 0){