De PHPhulp kroeg
Array to string conversion
mysqli_result Object ( [current_field] => 0 [field_count] => 3 [lengths] => [num_rows] => 1 [type] => 0 )
Notice: Array to string conversion in C:\USB WebServer\root\Youtube18\view.php on line 16
Code (php)
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<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id DESC";
$res = mysqli_query($conn, $sql);
print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
echo $images;
?>
<div class = "alb">
<img src = "images/<?$images?>">
</div>
<?php }
}
?>
</body>
<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id DESC";
$res = mysqli_query($conn, $sql);
print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
echo $images;
?>
<div class = "alb">
<img src = "images/<?$images?>">
</div>
<?php }
}
?>
</body>
<html>
Iemand een idee?
Code (php)
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<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id DESC";
$res = mysqli_query($conn, $sql);
//print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
// print_r ($images);
?>
<div class = "alb">
<img src = "images/<?$images['image']?>">
</div>
<?php }
}
?>
</body>
<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id DESC";
$res = mysqli_query($conn, $sql);
//print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
// print_r ($images);
?>
<div class = "alb">
<img src = "images/<?$images['image']?>">
</div>
<?php }
}
?>
</body>
<html>
Wat ontbreekt er nog meer. En ja het plaatje staat in uploads
Code (php)
1
<?=$images['image'];?>
je wilt de bestandsnaam wel zichtbaar maken.
Gewijzigd op 01/06/2022 21:35:30 door - Ariën -
Code (php)
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<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id DESC";
$res = mysqli_query($conn, $sql);
//print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
// print_r ($images);
?>
<div class = "alb">
<img src = "images/<?$images['image']?>">
<?=$images['image'];?>
</div>
<?php }
}
?>
</body>
<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id DESC";
$res = mysqli_query($conn, $sql);
//print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
// print_r ($images);
?>
<div class = "alb">
<img src = "images/<?$images['image']?>">
<?=$images['image'];?>
</div>
<?php }
}
?>
</body>
<html>
Ik krijg de naam van het betand wek te zien maar niet het plaatjes zelf.
het plaatje wat ik zie:
https://ibb.co/pLjyXWc
Dan zie je vast wel wat er fout gaat.
Code (php)
Ik neem aan dat je onder de afbeelding de titel wil zien.
HDM_User2.php
Code (php)
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<?php
session_start();
if(isset($_SESSION['username']))
{
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="../sidebar3.css">
<link rel="icon" href="../../../../favicon.ico" type="image/x-icon"/>
<title>Helpdeskmedewerker</title>
</head>
<body>
<body>
<div id="container">
<div id="sidebar">
<ul>
<li><a href= "../userhome.php">Home</a></li>
<li><a href= "HDM_User2.php">Groepsdynamica</a></li>
</ul>
<div id="sidebar-content" style="height: 50px"></div>
</div><!--
--><div id="content">
<br>
<!DOCTYPE html>
<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id ASC";
$res = mysqli_query($conn, $sql);
//print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
//print_r ($images);
?>
<div class = "alb">
<img src = "images/<?php echo $images['image']; ?>"><!--Plaatje-->
<?php echo $images['title']; ?><!--Titel-->
</div>
<?php }
}
?>
</body>
<html>
<br>
session_start();
if(isset($_SESSION['username']))
{
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="../sidebar3.css">
<link rel="icon" href="../../../../favicon.ico" type="image/x-icon"/>
<title>Helpdeskmedewerker</title>
</head>
<body>
<body>
<div id="container">
<div id="sidebar">
<ul>
<li><a href= "../userhome.php">Home</a></li>
<li><a href= "HDM_User2.php">Groepsdynamica</a></li>
</ul>
<div id="sidebar-content" style="height: 50px"></div>
</div><!--
--><div id="content">
<br>
<!DOCTYPE html>
<html>
<body>
<a href ="index.php"></a>
<?php
require_once "connection.php";
$sql = "SELECT * FROM imageupload ORDER BY id ASC";
$res = mysqli_query($conn, $sql);
//print_r ($res);
if(mysqli_num_rows($res)> 0)
{
while($images = mysqli_fetch_assoc($res))
{
//print_r ($images);
?>
<div class = "alb">
<img src = "images/<?php echo $images['image']; ?>"><!--Plaatje-->
<?php echo $images['title']; ?><!--Titel-->
</div>
<?php }
}
?>
</body>
<html>
<br>
index.php
Code (php)
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<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form method="post" enctype="multipart/form-data">
<label>Titel</label>
<input type="text" name="title">
<label>File Upload</label>
<input type="File" name="file">
<input type="submit" name="submit">
</form>
</body>
</html>
<?php
//verbinding maken met de database
//$conn = mysqli_connect('localhost', 'root', 'usbw', 'imageupload');// de laatste is de naam van de dadatabase
require_once "connection.php";
if (isset($_POST["submit"]))
{
//file title
$title = $_POST["title"];
//file name
$name = $_FILES["file"]["name"];
//temporary file name to store file
$tname = $_FILES["file"]["tmp_name"];
//upload directory pad
$uploads_dir = 'images';
//Kopieer de dabestanden
move_uploaded_file($tname, $uploads_dir.'/'.$name);
//SQL om de de documenten in de db te zetten
$sql = "INSERT INTO imageupload(title, image) VALUES('$title','$name')";
//echo $sql;
if(mysqli_query($conn, $sql))
{
echo "File Sucessfully uploaded";
}
else{
echo "Error";
}
}
?>
Daarnaast nog 2 plaatjes:
https://ibb.co/bbKNYRw
https://ibb.co/mh9sQS7
Wie kan me helpen?
Gewijzigd op 07/06/2022 23:06:13 door - Ariën -
- Klopt het pad wel?
- Heb je al in de Debugging-tool van je browser gekeken waar die de afbeeldingen ophaalt?
Debugging-tool is altijd een aanrader. ken je het niet, leer dan hoe het werkt.
Het is altijd de redder in nood.
Gewijzigd op 07/06/2022 23:15:45 door - Ariën -
Ik heb het allemaal werkend gekregen. Vervolgens een dikken 300 en 500 bladzijdes er in krijgen is natuurlijk monnikenwerk. Ik heb dus Libre Calc gebruikt (of misbruikt!)
PLaatje
https://ibb.co/Lppwmyf
Groetjes
Ed
Dit topic is gesloten.