$_FILES Image 2x uploaden en 1 daarvan verkleinen
zover was ik al:
Code (php)
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foreach ($_FILES["image"]["error"] as $key => $error) {
if (($error == UPLOAD_ERR_OK)&&($_FILES["images"]["size"] < 1)) {
$tmp_name = $_FILES["image"]["tmp_name"][$key];
$image = $_FILES["image"]["name"][$key];
move_uploaded_file($tmp_name, "../upload/screenshot/$image");
$query = mysql_query("INSERT INTO .......)");
}
}
if (($error == UPLOAD_ERR_OK)&&($_FILES["images"]["size"] < 1)) {
$tmp_name = $_FILES["image"]["tmp_name"][$key];
$image = $_FILES["image"]["name"][$key];
move_uploaded_file($tmp_name, "../upload/screenshot/$image");
$query = mysql_query("INSERT INTO .......)");
}
}
Gewijzigd op 02/09/2010 16:22:23 door Stefan Renne
Code (php)
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$max = mysql_fetch_object(mysql_query("SELECT max(`sid`) as `sid` FROM `screenshots`"));
$screenid = $max->sid+1;
$screenid = $max->sid+1;
Kan gewoon auto increment.
Code (php)
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move_uploaded_file($tmp_name, "../upload/screenshot/$image");
$query = mysql_query("INSERT INTO `screenshots` VALUES (NULL, '$image', NOW())");
$query = mysql_query("INSERT INTO `screenshots` VALUES (NULL, '$image', NOW())");
Vars buiten een string, backtics zijn vies en niet nodig.